C++ :

#include <bits/stdc++.h>
using namespace std;

int n;
int a, b, c, d, e, f;
int ans = 0;

// 求环状的差值
int fun(int x, int y) {
    if (abs(x - y) < n - abs(x - y)) {
        return abs(x - y);
    } else {
        return n - abs(x - y);
    }
}

int main() {
    cin >> n;
    cin >> a >> b >> c;
    cin >> d >> e >> f;

    // 枚举3个数的所有的可能: i, j, k
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= n; j++) {
            for (int k = 1; k <= n; k++) {
                // 如果和一组数“接近”，则符合要求
                if (fun(i, a) <= 2 && fun(j, b) <= 2 && fun(k, c) <= 2 ||
                    fun(i, d) <= 2 && fun(j, e) <= 2 && fun(k, f) <= 2) {
                    ans++;
                }
            }
        }
    }

    cout << ans;
    return 0;
}